What are the radius and the center of the circle x^2-6x+y^2-2y=14 ?

Given the equation of the
circle:

x^2 - 6x + y^2 - 2y =
14

We need to find the radius and the center of the
circle.

Then, we need to rewrite into the standard form as
follows:

(x-a)^2 + (y-b)^2 = r^2 such that (a,b) is the
center and r is the radius.

To rewrite we need to complete
the squares.

==> x^2 - 6x + 9 -9 + y^2 - 2y + 1 -1 =
14

==> (X-3)^2 + (y-1)^2 - 9 -1 =
14

==> (x-3)^2 + (y-1)^2 =
24

Then we conclude
that:

The center is the point (3,1) and the
radius is r=sqrt24= 2sqrt6